2009年9月5日星期六
2009年8月16日星期日
How to Solve a 4x4x4 Rubik Cube
It has been some time since i entered a post. Have been feeling very hectic and thus needed some relaxation. It has also been a long time since I visited this blog, and I felt some refreshing moments by reading my own blog. So now, I will continue with the last post with "How to Solve a 4x4x4 Rubik Cube." Enjoy!
The Easiest 4x4 Rubik's Cube Tutorial
The Easiest 4x4 Rubik's Cube Tutorial
2009年1月2日星期五
How to Solve a 3x3x3 Rubik Cube
I found a good video teaching to solve a 3x3x3 rubik cube and I would like to share it with you.
Subsequent postings will be the 4x4x4 and 2x2x2 rubik cubes.
Easiest 3x3 Rubik's Cube Tutorial You Will Find
2008年10月31日星期五
2008年10月30日星期四
Number Puzzle: Same total for every row, column, diagonal
Do you remember watching The Legend of the Condor Heroes (射鵰英雄傳) (TVB, 1994) where Guo Jing (郭靖) and severely injured Huang Rong (黃蓉) were at Ying Gu's (瑛姑) hut where Ying Gu challenged them to solve a 3x3 square puzzle by filling in numbers 1-9 to total the same in every row, column, and diagonal? Have you wondered how Huang Rong solve it? I'll try to explain it here.
A 3x3 square:
1) Start with "1" in the center square in the first row. From here, add in numbers in sequence, in a diagonally right up direction.
2) There is no more square to the top right diagonal of square 1, therefore, you put the next number, "2" to the right column last row.
3) To put "3", again, there is no more square to the top right diagonal of 2, therefore, you put it to the row above "2" at the most left column.
4) As you go to the top right diagonal of "3", it is being occupied by "1", therefore you proceed one square down and put "4".
5) There is an empty square to the top right diagonal of "4", therefore, fill "5" into the square, followed by "6" to the top right diagonal of "5".
6) To enter "7", there is no square to the top right diagonal of "6" and also no column to the right of "6". Therefore, you fill "7" in the square below
"6".
7) To enter "8", there is no square to the top right diagonal of "7", but there is a row above "7", therefore, you enter "8" in the row above "7", and to the most left column.
8) To enter the last number "9", again there is no square to the top right diagonal of "8", therefore "9" is entered in the column to the right of "8" but to the last row.
Do you get it now? In a 3x3 square, every column, row, and diagonal adds up to 15.
A 3x3 square:
1) Start with "1" in the center square in the first row. From here, add in numbers in sequence, in a diagonally right up direction.2) There is no more square to the top right diagonal of square 1, therefore, you put the next number, "2" to the right column last row.
3) To put "3", again, there is no more square to the top right diagonal of 2, therefore, you put it to the row above "2" at the most left column.
4) As you go to the top right diagonal of "3", it is being occupied by "1", therefore you proceed one square down and put "4". 5) There is an empty square to the top right diagonal of "4", therefore, fill "5" into the square, followed by "6" to the top right diagonal of "5".
6) To enter "7", there is no square to the top right diagonal of "6" and also no column to the right of "6". Therefore, you fill "7" in the square below
"6".7) To enter "8", there is no square to the top right diagonal of "7", but there is a row above "7", therefore, you enter "8" in the row above "7", and to the most left column.
8) To enter the last number "9", again there is no square to the top right diagonal of "8", therefore "9" is entered in the column to the right of "8" but to the last row.
Do you get it now? In a 3x3 square, every column, row, and diagonal adds up to 15.
This formula can be used for all odd-numbered squares, e.g., 5x5, 7x7, 9x9, and so on.
Try solving the 5x5 square.
Below is the answer for the 5x5 square.
订阅：
博文 (Atom)